angular regex to get last parts of an url

Asked May 03 '18 at 15:39

Active May 03 '18 at 15:39

Viewed 21 times

I would like to get the last parts of an url in order to know in which "case" I am : edit, add, delete or list. Moreover, I would like to know what is the page where I am.

Here some examples :

xxxxx/xxxx/items/add

Page: items
case: add

xxxxx/xxxx/items/edit/:id

Page : items
case: edit
id: xxxx

xxxxx/xxxx/items

Page : items
case: list

For now, I can determine if I'm edit or add case by using includes function. I can also get the last part of my url but, only the last part. So if i'm on edit case, I only get the id.

Thank you very much for any advices/solutions !

asked May 03 '18 at 15:39

Joe Allen

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Are you using the Angular router? – Oscar Paz May 03 '18 at 15:41
You definitely need to have a look at [this](https://angular.io/api/router/ActivatedRoute) – bugs May 03 '18 at 15:41
I'm using the router.events and RoutesRecognized. From here, I get the url – Joe Allen May 03 '18 at 15:43
May be a possible duplication of https://stackoverflow.com/questions/31556069/how-to-get-the-last-part-of-url-angularjs – abhi May 03 '18 at 15:44

angular regex to get last parts of an url

0 Answers0