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I have input files "input.dat" contain some values like this :

41611   2014    12  18  0   0
41615   2014    12  18  0   0
41625   2014    12  18  0   0
41640   2014    6   14  3   3
42248   2014    12  18  0   0
42323   2014    12  18  0   0
42330   2014    8   13  7   7
42334   2014    12  18  0   0
42335   2014    12  18  0   0
...

I have many dataset files but seems so many unwanted data How to delete many rows for this case 41640 and 42330 and its entire row values at instant. For now I used this script:

with open(path+fname,"r") as input:
    with open("00-new.dat","wb") as output: 
        for line in input:
            if line!="41640"+"\n":
                output.write(line)

The result: The data 41640 is still exist in output. Any ideas??

NightOwl19
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Azam
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  • Possible duplicate of [Deleting a specific line in a file (python)](https://stackoverflow.com/questions/4710067/deleting-a-specific-line-in-a-file-python) – NightOwl19 May 04 '18 at 05:58

1 Answers1

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You need to change your condition - how it is now it checks if the whole line is equal to 41640. Each line is instead equal to the whole row of data you are reading followed by a \n. Fixed version of your program looks like this:

with open("00-old.dat","r") as input:
with open("00-new.dat","wb") as output:
    for line in input:
        if "41640" not in line:
            output.write(line)

To delete multiple lines you can use all() combined with a list comprehension as for instance described in this post,

if all(nb not in line for nb in del_list):
    output.write(line)

where del_list is a list of values you want deleted, 

del_list = ["41615", "41640", "42334"]

Also, due to Python's operator precedence your original condition will always evaluate to True. That is because even if the 41640!=line was false, the \n is added to it and interpreted (after conversion) as True. Basically, the != is evaluated first, instead of the string concatenation followed by a !=.

atru
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