Handle Multiple APIs simultaneously

Question

I want to call two apis simultaneously. And the case is, when i got successful response of both apis, then only third api should be called. Here i won't use any flag or variable to check if both apis are successful. Please suggest if there is any way to do that.

Because It is not proper way to do that. Any variable shall not be used for just checking both api responses came or not. — Dhaval Trivedi, May 04 '18 at 13:05

score 1 · Accepted Answer · answered May 04 '18 at 07:58

1

You can use DispatchGroup

let group = DispatchGroup()

group.enter()
perform(request: first) {
    group.leave()
}

group.enter()
perform(request: second) {
    group.leave()
}

group.notify(queue: .main) {
    print("both done")
}

answered May 04 '18 at 07:58

Ivan Smetanin

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That's It. Thanks. :) – Dhaval Trivedi May 04 '18 at 15:53
@DhavalTrivedi You can approve my answer :) – Ivan Smetanin May 08 '18 at 06:19

score 1 · Answer 2 · answered May 04 '18 at 08:05

you can use Dispatch group to create a group of tasks

here example

// First, we create a group to synchronize our tasks
let group = DispatchGroup()

// The 'enter' method increments the group's task count…
group.enter()

ApiRequest1.Data { data in
    // …while the 'leave' methods decrements it
    group.leave()
}
group.enter

ApiRequest2.Data { data in
    group.leave()
}

// This closure will be called when the group's task count reaches 0
group.notify(queue: .main) { [weak self] in

}

Thanks for the explaination. Its working fine. – Dhaval Trivedi May 04 '18 at 15:48 — Dhaval Trivedi, May 04 '18 at 15:48

Handle Multiple APIs simultaneously

2 Answers2