testing for number or NOT integer in if/while/for

Question

I am trying to get a user to input a number into a calculator program. The goal right now is to keep giving the user an error message and asking to reenter a number until they enter a real number.

here is some code that I've done:

number_1 = input("Enter your first number here! ")
while number_1 == int():
    print("Well done for entering a number!")

`int()` returns `0`, so you are checking if `number_1 == 0` – juanpa.arrivillaga May 07 '18 at 06:07 — juanpa.arrivillaga, May 07 '18 at 06:07

score 1 · Answer 1 · answered May 07 '18 at 06:06

1

you need to use isdigit()

number_1 = input("Enter your first number here! ")
if str(number_1).isdigit():
    print("Well done for entering a number!")

answered May 07 '18 at 06:06

Keerthana Prabhakaran

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score 0 · Answer 2 · answered May 07 '18 at 06:14

How about try: except:?

def my_input(number_1):
    while 1:
        try:
            int(number_1)
            return number_1
        except:
            print("It is not an integer.")
            number_1 = input("Give an integer: ")

int1 = input("Enter your first number here! ")
my_input(int1)
print("Well done for entering a number!")

You may have to change int(number_1) to float(number_1) (and input text(s)) depending on your implementation.

testing for number or NOT integer in if/while/for

2 Answers2