how to parse xml to java in nodelist

Question

that is my xml

<?xml version = "1.0" encoding = "UTF-8"?>
 <ns0:GetADSLProfileResponse xmlns:ns0 = "http://">
<ns0:Result>
    <ns0:eCode>0</ns0:eCode>
    <ns0:eDesc>Success</ns0:eDesc>
</ns0:Result>
</ns0:GetADSLProfileResponse>

that is my code in java I need to know how to start in this I tried some code online but still did not solve my problem how to get the values in the result to loop in it and get 0 in ecode and Success in eDesc

CustomerProfileResult pojo = new CustomerProfileResult();
    String body = readfile();
    System.out.println(body);
    try {  
        DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
        DocumentBuilder db = dbf.newDocumentBuilder();
        Document dom = db.parse(new InputSource(new StringReader(body)));
        XPath xpath =XPathFactory.newInstance().newXPath();

        XPathExpression name = xpath.compile("/xml/GetADSLProfileResponse/Result");
        NodeList nodeName = (NodeList) name.evaluate(dom, XPathConstants.NODESET);

        if(nodeName!=null){

        }

I've had great experience with JacksonXML. If you can pull in that library, it'll do the low-level parsing for you. https://github.com/FasterXML/jackson-dataformat-xml — Sean, May 09 '18 at 14:18

Mincong Huang · Accepted Answer · 2018-05-09T19:53:36.927

Summary

You can try to following expression which allows you to select nodes without caring the namespace ns0:

/*[local-name()='GetADSLProfileResponse']/*[local-name()='Result']/*

Explanation

In your syntax, several parts were incorrect. Let's take a look together. XPath syntax /xml means that the root node of the document is <xml>, but the root element is <ns0:GetADSLProfileResponse>; GetADSLProfileResponse is incorrect too, because your XML file contains a namespace. Same for Result:

/xml/GetADSLProfileResponse/Result

In my solution, I ignored the namespace, because your namespace provided is incomplet. Here's a full program to get started:

String XML =
  "<?xml version = \"1.0\" encoding = \"UTF-8\"?>\n"
      + "<ns0:GetADSLProfileResponse xmlns:ns0 = \"http://\">\n"
      + "  <ns0:Result>\n"
      + "    <ns0:eCode>0</ns0:eCode>\n"
      + "    <ns0:eDesc>Success</ns0:eDesc>\n"
      + "  </ns0:Result>\n"
      + "</ns0:GetADSLProfileResponse> ";
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
DocumentBuilder builder = factory.newDocumentBuilder();
Document document;
try (InputStream in = new ByteArrayInputStream(XML.getBytes(StandardCharsets.UTF_8))) {
  document = builder.parse(in);
}

XPath xPath = XPathFactory.newInstance().newXPath();
XPathExpression expr = xPath.compile("/*[local-name()='GetADSLProfileResponse']/*[local-name()='Result']/*");

NodeList nodeList = (NodeList) expr.evaluate(document, XPathConstants.NODESET);
for (int i = 0; i < nodeList.getLength(); i++) {
  Node node = nodeList.item(i);
  System.out.println(node.getNodeName() + ": " + node.getTextContent());
}

It prints:

ns0:eCode: 0
ns0:eDesc: Success

how to parse xml to java in nodelist

1 Answers1

Summary

Explanation