0
for x in range(0,len(b)):
    if x+1 < len(b):
        if b[x][1] == 'B' and b[x+1][1] == 'B':
            a.append([b[x][0], b[x][2]])
        elif b[x][1] == 'B'and b[x+1][1] == 'I':
            kata = b[x][0]
            a = 1
            while True:
                if x+a < len(b):
                    if b[x+a][1] == 'I':
                        kata += ' ' + b[x+a][0]
                        a += 1
                    elif b[x+a][1] == 'B':
                        break
                else:
                    break
            a.append([kata, b[x][2]])
    else:
        if b[x][1] == 'B':
            a.append([b[x][0], b[x][2]])

Can someone help me to convert the for-loop become while-loop? and the while-loop stay while-loop?

k_ssb
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ian lord perdana
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  • Do you have a particular reason to want to do that? A `while` loop offers no advantages here. If this is purely for exercise, see my answer below. – Zinki May 14 '18 at 08:11
  • Maybe you should convert the `while` loop into a `for` loop: `for y in range(x+1, len(b)):` where `y = x+a`... – jferard May 14 '18 at 09:50

1 Answers1

0

a for loop of the form 

for x in y:
    #code

can always be turned into a while loop of the form 

i=0
while i < len(y):
    x = y[i]        
    #code
    i += 1

since x in your case is just iterating through values 0 to len(b) you can further reduce it down to:

x=0
while x < len(b):       
    #code
    x += 1
Zinki
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  • This isn't *strictly* true – it won't work for generators, for instance. For that you would need to get an iterator over y via `it = y.__iter__()`, then do `try: x = it.next()` and catch `StopIteration`, per the [iterator protocol](https://stackoverflow.com/a/16301581/5951320). – ash May 14 '18 at 08:45