print many values by a loop in java

Question

public class teste {

public static void main(String[] args) {
    int t1=5;
    int t2=10;
    int t3=30;

    for(int i=1;i<4;i++)
    {
        System.out.println("t"+i);
    }

}}

Hi guys I don't know if it exists in java but I wanna print t1 t2 t3 by a loop, for example for i=1 t(i=1) => t1 so it will give us 5, how can I do that, and thank you all.

You want to use an array. https://docs.oracle.com/javase/tutorial/java/nutsandbolts/arrays.html — Bill the Lizard, May 14 '18 at 17:37
You need to create an array like: `int[] t = {5. 10, 30, etc..}` — Omar Silva, May 14 '18 at 17:37
Relevant: https://stackoverflow.com/questions/6729605/assigning-variables-with-dynamic-names-in-java — Gary, May 14 '18 at 17:45

Pavneet_Singh · Answer 1 · 2018-05-14T17:45:16.373

3

3 variables mean three atomic statements are required but to access them in continuous way , collect them in some container like array so use

int t1=5;
int t2=10;
int t3=30;
int[] arr = {t1,t2,t3}; // array index start from 0
//           0  1  2
// arr[0] is 5
// arr[1] is 10 and so on

for(int i=0;i<3;i++)
{
    System.out.println(arr[i]);
}

Other option: use var args which is still sort of an array but flexible like

static void printNums(int... arr){
    for(int i=0;i<arr.length;i++)
    {
        System.out.println(arr[i]);
    }
}

and call it like

printNums(t1,t2);
printNums(t1,t2,t3);
printNums(1,2,3,4,5,6);

edited May 14 '18 at 17:45

answered May 14 '18 at 17:37

Pavneet_Singh

36,884
5
53
68

I know this method but I'm looking for others thank you – Ayoub Eloumari May 14 '18 at 17:41
@AyoubEloumari what makes you think there are others? – Andy Turner May 14 '18 at 17:43

score 1 · Answer 2 · answered May 14 '18 at 17:38

1

There is no way to call a variable using String or int or whatever

But that's the purpose of arrays, first index is 0 and last one is length-1 (here 2)

int[] t = new int[]{5, 10, 30};

for(int i=0 ; i<t.length ; i++){
    System.out.println(t[i]);
}
// gives
5
10
30

answered May 14 '18 at 17:38

azro

53,056
7
34
70

I know this method but I'm looking for others thank you – Ayoub Eloumari May 14 '18 at 17:41
1

@AyoubEloumari others ? With which specificities ? – azro May 14 '18 at 17:42
like I told in the question above and also it exists in php – Ayoub Eloumari May 14 '18 at 17:44
@AyoubEloumari Java is not PHP (thank the maker). There is no reason to assume that features in one language would exist in another. – Andy Turner May 14 '18 at 17:45
@AyoubEloumari curious to know how PHP does that – azro May 14 '18 at 17:46

score 0 · Answer 3 · edited May 14 '18 at 20:44

0

The for loop will only print the values t1, t2,t3 only because you initialized the t1 as a variable and in your output you using it as a text by including quotation marks. Try this code.

public class test
{
    public static void main(String[] args) {
        int [] arrValue = {5 , 10 , 30};

        for(int i= 0; i <4; i++)
        {
            System.out.println("t"+i + "=" + arrValue[i]);
        }
    }
}

edited May 14 '18 at 20:44

Gary

13,303
18
49
71

answered May 14 '18 at 17:46

Sandile Stanza Maseko

11
1

Same answer as mine + will throw ArrayOutOfBoundsException ^^ – azro May 14 '18 at 17:49

score 0 · Accepted Answer · answered May 14 '18 at 18:26

Can "t" + i be considered a key (instead of a dynamic variable name which is not supported)? If that fits the context then a Map could be used. For example:

public static void main(String[] args) {
    Map<String, Integer> tVals = new HashMap<>();
    tVals.put("t1", 5);
    tVals.put("t2", 10);
    tVals.put("t3", 30);

    for (int i = 1; i < 4; i++) {
        System.out.println(tVals.get("t" + i));
    }
}

score -1 · Answer 5 · edited May 14 '18 at 17:59

Please tell me if I don't understand your question. What you seem to be trying is to print t1 t2 and t3, but based on the i of the for loop right? So you think that t + i should first be t1, then t2 then t3 and finally output those values. That doesn't work for any language this way. First of all, t is a char, while 1 2 or 3 is an integer. Secondly, if you put it like that in System.out.println it basically means "print out t and then i", instead of "print out what t+i would be (as initialized)". I might not be very clear with explaining. Anyway, you should use an array.

Try the following:

class test{

    public static void main(String[] args) {

        int[] anArray = { 
        5, 10, 30,
    };

        for(int i = 0; i < anArray.length; i++)
        {
            System.out.println(anArray[i]);

        }
    }

}

I wrote this when nobody answered, i cant really do smth about the fact that everyone reacted at the same time. Secondly, this code is correct idk what ur talking about? Maybe learn java be4 talking Also, some people's codes would give out of bound exception, mine doesnt — javascaped, May 14 '18 at 17:58

print many values by a loop in java

5 Answers5