Append string to start and end of line regex (notepad++)

Question

I'm having trouble formulating how to append the following to the beginning and end of the line in notepad++ :

Beginning ('

End ,10)

I tried using the following, but none would even match the beginning of the line:

%s/.*/"&"

^

When I used ^ this matched the beginning of line but if I tried to appending ^( it would just replace the line with ^ .

My sample data looks like:

/.../.../.../.../.../
\…..\\\…..\\\…..\\\
%00../../../../../../etc/file
%00/etc/file%00

Thanks

score 6 · Accepted Answer · answered May 16 '18 at 12:16

6

To match the beginning of line, use ^ anchor. Since ( is part of regex, it needs to be escaped:

Same goes for matching end-of-line: use $ and ,10\):

answered May 16 '18 at 12:16

Sergey Kalinichenko

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Life saver, thanks! I'll accept when I can – Jshee May 16 '18 at 12:20

score 1 · Answer 2 · answered May 16 '18 at 12:16

1

Use this:

^(.*)$

to capture everything.

Then replace with $'\1,10$,

where $' is the beginning part, ,10$ is the end, and \1 is what you capture.

answered May 16 '18 at 12:16

CinCout

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score 0 · Answer 3 · answered May 16 '18 at 12:17

Search for ^.*$, replace by ('$0,10).

$0 is a back-reference referencing the full match, ^ and $ are anchors that respectively match the start of the string and its end in the search pattern (they have no meaning in a replacement pattern, in which they are understood as the literal characters).

Append string to start and end of line regex (notepad++)

3 Answers3