Error while sending Mail with attachement in Python

Question

import smtplib, os
from email.mime.multipart import MIMEMultipart
from email.mime.base import MIMEBase
from email.mime.text import MIMEText
from email.utils import formatdate
from email import encoders

os.chdir(path)


def send_mail(send_from,send_to,subject,text,files,server,port,username='',password='',isTls=True):
    msg = MIMEMultipart()
    msg['From'] = send_from
    msg['To'] = send_to
    msg['Date'] = formatdate(localtime = True)
    msg['Subject'] = 'Test'
    msg.attach(MIMEText(text))

    part = MIMEBase('application', "octet-stream")
    part.set_payload(open("Olaf.xlsx", "rb").read())
    encoders.encode_base64(part)
    part.add_header('Content-Disposition', 'attachment; 
    filename="Olaf.xlsx"')
    msg.attach(part)

    smtp = smtplib.SMTP('smtp.web.de', 587)
    smtp.starttls()
    smtp.login('test@test.de', 'pw')

At this part the error occurs: NameError: name 'msg' is not defined. But whats wrong? Here is where I got the code from: add excel file attachment when sending python email

    smtp.sendmail('xy','xyz', msg.as_string())

    smtp.quit()

Can you fix the indentation of the code in your question. It looks like you are trying to access the variable `msg` defined _in_ the function, outside of it — DavidG, May 17 '18 at 08:30
I wonder how doesn't it raise a `NameError` on `os.chdir(path)` as you haven't defined `path` anywhere. Then it should raise a `SyntaxError` on the `part.add_header...` line. Strangely enough, the only error your code shouldn't be rising is the one you're saying it does. — zwer, May 17 '18 at 09:00
In my code the path is wirtten in G:\ etc. just for the example i renamed it. So it works now, Thanks for the fast answers. — Tobias G., May 17 '18 at 09:47

score 0 · Answer 1 · answered May 17 '18 at 09:30

You can try the below code:

import smtplib, os
from email.MIMEMultipart import MIMEMultipart
from email.MIMEBase import MIMEBase
from email import Encoders
from email.mime.text import MIMEText

emaillist=['to@gmail.com'] # Receipient email address
msg = MIMEMultipart('mixed')
msg['Subject'] = 'Arrest Warrent' # mail subject line
msg['From'] = 'xyz@gmail.com' # From email address
msg['To'] = ', '.join(emaillist)

part = MIMEBase('application', "octet-stream")

# Provide the path of the file to be attached in the mail
part.set_payload(open('C:'+os.sep+'Users'+os.sep+'abhijit'+os.sep+'Desktop'+os.sep+'WarrentDetails.txt', "rb").read())
Encoders.encode_base64(part)

part.add_header('Content-Disposition', 'attachment; filename="WarrentDetails.txt"')

msg.attach(part)
msg.add_header('To', msg['From'])
text = "Dear Sir, \n\n An arrest warrent has been generated due to XYZ reason by ZZZ complain.\n YOU MUST APPEAR IN PERSON TO RESOLVE THIS MATTER. \n\n Regards,\n FBI :)"
part1 = MIMEText(text, 'plain')
msg.attach(part1)

# provide SMTP details of the host and its port number
server = smtplib.SMTP_SSL("smtp.gmail.com",465)
# If the host supports TLS then enable the below 2 lines of code
# server.ehlo()
# server.starttls()

server.login("xyz@gmail.com", "password")

server.sendmail(msg['From'], emaillist , msg.as_string())

More details on this can be found at this blog.

Error while sending Mail with attachement in Python

1 Answers1