import random
words=['left','none','super','bale']
i=4
luke=[]
nexa=[]
while i>0:
new=random.choice(words)
luke=luke.append(new)
i=i-1
for k in range(0,len(words)):
if words[k]==new:
nexa=words[0:k]+words[(k+1):4]
else:
continue
words=nexa
print(luke)
I tried something like this but it is clearly not working any kind of help is really appreciated.
You've over-complicated things. You can shuffle the list in-place and then iterate it, which guarantees that you can only print each word once, provided that you don't have duplicate words (in which case you could convert to a set() beforehand).
import random
words = ['a', 'b', 'c']
random.shuffle(words)
for word in words:
print(word)
Because this works in place, you'll lose the initial ordering. If you need to retain the initial ordering then you can shuffle a copy of the list.
import random
words = ['a', 'b', 'c']
word_copy = words.copy()
random.shuffle(word_copy)
for word in word_copy:
print(word)
import random
words = ['left', 'none', 'super', 'bale']
random.shuffle(words)
print(words)
