You can also approach this with LINQ, by using the index overload of .Select
to retain a running count of the line numbers, and then to group them into groups of 3 - I've used integer division to Floor
the line index, 3 at a time, but there are likely other suitable ways.
var groups = values.Select((s, idx) => (Index: idx / 3, Value: s))
.GroupBy(x => x.Index);
Where each item in the groups above will be IEnumerable<(Index, Value)>
.
You'll also need to be wary of newlines - these may be \r\n
in Windows, not just the \n
you've indicated.
Here's an example:
var a =
@"A2,
10.22,
-57,
A,
10.23,
-68,
A2,
10.24,
-60,
LB,
10.25,
-62,";
var values = a.Split(new[] { "\r\n", "\r", "\n" }, StringSplitOptions.None);
var groups = values.Select((s, idx) => (Index: idx / 3, Value: s))
.GroupBy(x => x.Index);
foreach (var grp in groups)
{
Console.WriteLine(string.Join("", grp.Select(x => x.Value)));
}
Since you've already got commas at the end of each string (including the last one), there's no need to add another separator.
Output:
A2,10.22,-57,
A,10.23,-68,
A2,10.24,-60,
LB,10.25,-62,