Is str.count() wrong?

Question

I'm having fun with some challenges and one of them makes me count substrings in a string. I have a problem specifically with "banana":

str = "banana"
print(str.count("ana"))

This should return 2 because "ana" appears two times:

b a n a n a
  a n a
      a n a

But str.count("ana") returns only 1. I've also tried with regexp:

import re
str = "banana"
print(len(re.findall("ana", str)))

But it also returns 1. Am I missing something?

thank you!

As the docs say, `str.count` counts _non-overlapping_ occurrences of the the substring. — PM 2Ring, May 22 '18 at 19:03
As an aside, you shouldn't call your variables `str` or any other built-in types/functions. — sjw, May 22 '18 at 19:05
You can use regex module which supports overlapping pattern matching. print(len(regex.findall("ana", str,overlapped=True))) — Ash Ishh, May 22 '18 at 19:14

score 0 · Answer 1 · answered May 22 '18 at 19:03

0

Yes, you are missing something.

answered May 22 '18 at 19:03

jeremysprofile

1 Answers1