Java Integer object instantiation with parameters

Question

This question is a part of OCP test series .

> Integer i=new Integer(100_00);

I tried to understand how this works but so far i have only got this much that this is one of a message format . Please provide some clarity as to how we can pass a numeric value with a underscore . Pardon me if this is a simple concept but i am kind of anxious to know this .

score 5 · Accepted Answer · answered May 22 '18 at 23:08

5

Java allows numeric literals with _ for better readability.

For example:

int i = 10_000;
float pi =      3.14_15F;

answered May 22 '18 at 23:08

jmj

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In other words, `10_000`, `100_00` and `10000` are all the same; they all mean "ten thousand". – Kevin Anderson May 22 '18 at 23:11
Thanks Jigar and Kevin . Your answers combined answer this . So this is just for readability . After your code gets compiled, these underscores are removed in bytecode stream ? – Nishant_Singh May 22 '18 at 23:15
The compilation process itself deals with the underscores. – Louis Wasserman May 22 '18 at 23:26
I am sorry deals ? – Nishant_Singh May 22 '18 at 23:32
correct, `int i = 100 `and `int i = 1_0_0 `compiles to same thing – jmj May 22 '18 at 23:45

Java Integer object instantiation with parameters

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