how to read a file from resources folder in properties file

Question

I have a file under resources folder src/test/resources/file.xml and another under src/test/resources/test.properties. I want to set a property in properties file to point to file.xml. How can I achieve this?

Say I have a property

test.file = file.xml

and my java class reads the file as follows:

File cert = new File(fileName); // fileName is the value of test.file

This does not work however.

It's not quite clear what the issue is. What error are you getting? — Bhesh Gurung, May 23 '18 at 15:36
possible duplicate of https://stackoverflow.com/questions/22370051/how-to-write-values-in-a-properties-file-through-java-code — Laxmikant, May 23 '18 at 15:40
You need either a full path or a `URI` instance to create an instance of [`File`](https://docs.oracle.com/javase/7/docs/api/java/io/File.html). — Bhesh Gurung, May 23 '18 at 15:41
@question_tech you need to use the relative path to get the full name. Please check my answer — Subburaj, May 23 '18 at 16:54

score 2 · Answer 1 · answered May 23 '18 at 15:32

2

You can use Properties class to read and write to config files.

answered May 23 '18 at 15:32

Jeffin Manuel

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score 1 · Answer 2 · answered May 23 '18 at 16:51

Firstly, you need to find the relative path for the resources using below steps
Secondly, you can configure and load the test properties file
Finally, read the property value and append with the resource
directory

Code:

String rootDirectory=System.getProperty("user.dir");
String resourceDirectory=rootDirectory+"src/test/resources/";

//Configure property File
Properties properties = new Properties();
properties.load(new FileInputStream(resourceDirectory+"test.properties"));
PropertyConfigurator.configure(properties);

//To get the property value
String tempFileName=properties.getProperty("test.file");

//filename Needs to be changed as below
File cert = new File(resourceDirectory+tempFileName);

how to read a file from resources folder in properties file

2 Answers2