I want to draw simple polygon that means there is no self-intersecting in the polygon using x & y locations. But what I got for the result is butterfly shape of polygon.
I know that if I change li_feasible_points to [[0,2],[2,2],[4,0],[2,0]] in order to draw simple polygon IN THIS TIME.
But WHAT I WANT is to draw simple polygon without self-intersecting by ANY list of corner points locations. Is there any way to solve this problem?
Here is my code and my result below.
from matplotlib import pyplot as plt
fig, ax = plt.subplots(figsize=(6, 6))
x_lim = 5
y_lim = 10
x = np.linspace(0, x_lim)
y = np.linspace(0, y_lim)
li_feasible_points = [[0.0, 2.0], [4.0, 0.0], [2.0, 0.0], [2.0, 2.0]]
line = plt.Polygon(li_feasible_points, closed=False, color='r', fill=True, edgecolor='r')
plt.gca().add_line(line)
plt.xlabel(li_var_names[0])
plt.ylabel(li_var_names[1])
plt.xlim(0, x_lim)
plt.ylim(0, y_lim)
plt.show()
I look forward to your help. Thank you.
