Python for-loop, range counter

Question

I have made a program that prints the each date of year. Is it possible to add a counter that will allow to limit the printable dates? I would print for example every 7 days. Thanks for any advice. The original code below.

def main():

    for month in range(1, 13):
        daymax = 32
        if month == 2:
            daymax = 29
        elif month == 4:
            daymax = 31
        elif month == 6:
            daymax = 31
        elif month == 9:
            daymax = 31
        elif month == 11:
            daymax = 31

        for day in range(1, daymax):
            print(day,".", month,".", sep="")


main()

Have a look at the [datetime](https://docs.python.org/3.6/library/datetime.html#module-datetime) module. — Thierry Lathuille, May 24 '18 at 19:43
This is a really strong candidate for datetimes and timedeltas. You'll get all sorts of benefits like leap-year support, time zones, etc. — g.d.d.c, May 24 '18 at 19:44
Also, have a look at the [`calendar` module](https://docs.python.org/3/library/calendar.html). — Martijn Pieters, May 24 '18 at 19:48

score 0 · Answer 1 · answered May 24 '18 at 19:44

0

Just use another counter variable, and check if it's a multiple of 7.

def main():
    counter = 0
    for month in range(1, 13):
        daymax = 32
        if month == 2:
            daymax = 29
        elif month == 4:
            daymax = 31
        elif month == 6:
            daymax = 31
        elif month == 9:
            daymax = 31
        elif month == 11:
            daymax = 31

        for day in range(1, daymax):
            if counter % 7 == 0:
                print(day,".", month,".", sep="")
            counter += 1

answered May 24 '18 at 19:44

Barmar

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@DeepSpace That doesn't work because months aren't a multiple of 7 days. – Barmar May 24 '18 at 19:48
7 days after January 28 is Feb 4, but that will print Feb 1. – Barmar May 24 '18 at 19:48
Indeed.......... – DeepSpace May 24 '18 at 19:50
@DeepSpace: `counter` is the *ordinal day in the year*, not the ordinal day in the month. – Martijn Pieters May 24 '18 at 19:51
Than you! This works, but I have still a little problem: Now printing begins on the first day of the month. The first day should be 3.1 and then every 7 days printing. – Hello May 25 '18 at 08:04
Hey again, I got this resolved. Thank you everybody! – Hello May 25 '18 at 09:09
@Hello Why should the first day be 3.1 instead of 1.1? – Barmar May 25 '18 at 14:31

score 0 · Answer 2 · answered May 24 '18 at 19:45

0

if day % 7 == 0

that should work. Try it.

answered May 24 '18 at 19:45

takethelongsh0t

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1
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11

Python for-loop, range counter

2 Answers2