I'm having a problem with the int() function. I tried to use it in a simple program, but remains not working. This is my short program. I use int() to turn the a variable from a str into a int. And use it to compeare with 2. But it returns an error, because it's still seen a as a str. What's happening??
a = '4'
int (a)
if a > 2:
print( "It's working" )
int(a) doesn't mutate a, it creates a new object and returns it. Try this:
a = '4'
i = int(a)
if i > 2:
print("It's working")
Notice that the new variable I created on line 2 has a different name from the one I created on line 1. It doesn't have to. In fact, sometimes it can be more readable to re-use the name:
a = '4' # Now `a` is a `str`
a = int(a) # Now `a` is an `int`
if a > 2:
print("It's working")
# or mutate the a by redefining a:
a = '4'
a = int(a)
if a > 2:
print("It's working")
Instead of type casting it before the for loop, you can keep "a" as a str and just type cast it to int in the for loop. This will preserve your str dataype while you will get your desired output.
a = '4'
if int(a) > 2:
print( "It's working" )
In your program. you are converting str to int only for that instance. You're not storing it anywhere. So your variable a points to the str which is stored before type casting it.
