Print JSON keys of an array within another array in PHP

Question

I have the following JSON code:

{
   "google.com": {
        "clicks": 23,
        "browsers": {
            "Chrome": 19,
            "Mozilla": 2,
            "Safari": 1
        }
    },
    "mcnitro.net": {
        "clicks": 87,
        "browsers": {
            "Chrome": 19,
            "Mozilla": 2,
            "Safari": 1
        }
    }
}

And I am endeavouring to print on the document page the arrays' names and their children. So far, I have tried the following PHP code:

<?php
    header("Content-type: text/javascript");
    $jsonString = file_get_contents('stats.json');
    $data = json_decode($jsonString, true);
    foreach($data->children() as $domain) {
        echo $data[$domain];
        foreach($data[$domain] as $value) {
            echo $value['clicks'];
        }
    }
?>

However, I am facing an issue in the error_log:

PHP Fatal error:  Call to a member function children() on array in /home/gamin167/public_html/ads/engine/300x250/gen.js.php on line 5

The result wanted was to have "google.com" and "mcnitro.net" printed, as well as their "clicks" property.

Any tip or advice will be highly appreciated! Thanks in advance!

What makes you think $data was an object that had a `children` method …? — CBroe, May 25 '18 at 07:08
`$data` will be an associative array, that which doesn't have a function named `children()`. `foreach($data->children() as $domain) {` should be replaced with `foreach($data as $k=>$doman){`.. — Romeo Sierra, May 25 '18 at 07:09
No idea, to be impartial. I am rather fresh to PHP and have discovered that composition of code on the Internet. — undefined, May 25 '18 at 07:11
`children()` looks more like an XML method, which is just another data file format. — Nigel Ren, May 25 '18 at 07:13

score 0 · Answer 1 · answered May 25 '18 at 07:09

You decode the string to an array with true yet you seem to try and use it as an object.
Also there is no need to loop twice.

foreach($data as $key => $domain) {
    echo $key . "\n";
    echo $domain['clicks'] . "\n\n";

}

output:

google.com
23

mcnitro.net
87

https://3v4l.org/D7FCY

score 0 · Answer 2 · answered May 25 '18 at 07:10

You cannot use ->children(). $data is an array with your json data, and you can use foreach to get key and value, like foreach ($data as $key => $value).

So here, to get your domain name, just do :

<?php
    header("Content-type: text/javascript");
    $jsonString = file_get_contents('stats.json');
    $data = json_decode($jsonString, true);
    foreach($data as $domain => $value) {
        echo $value['clicks'];
    }
?>

Print JSON keys of an array within another array in PHP

2 Answers2