unreachable code when trying to stop executing method if condition true

Asked May 26 '18 at 13:40

Active May 26 '18 at 13:54

Viewed 29 times

Good day!

Im currently trying to stop my method if one of the digits = 0. For some reason it says "unreachable code" at the point below:

    static void method(int y) {


    int dig1 = y % 10;
    int dig2 = y / 10 % 10;  //digits of y
    int dig3 = y /100 % 10;

    if (dig1 == 0);{         //if dig1 = 0, stop the method
       return; 
    }
     if (dig2 == 0);{      // unreachable code, but why?
        return;
     }
      .... and so on

How come it says unreachable code even if the condition is not true? y = numbers from 122 - 133 and the only number who is supposed to stop the method is 130 because of the 0. Could someone be this kind and explain it to me please? Thanks!

edited May 26 '18 at 13:54

asked May 26 '18 at 13:40

MarioF.

4

remove the `;` after the closing `)` in both `if`s. – luk2302 May 26 '18 at 13:41
1

Beside the @luk2302 correct suggestion, did you also make the typo `if (dig1 == 0)`? – zlakad May 26 '18 at 13:47

unreachable code when trying to stop executing method if condition true

0 Answers0