Error with if statment

Asked May 28 '18 at 15:37

Active May 28 '18 at 15:42

Viewed 28 times

I want to know why this code doesn't work properly: it should break when the input not 1 ,2 or 3

while True:
        try:
            aw = int(input('Number : '))

            if aw in [1,2,3] == False:
                print('give Number agian')
            else:
                print('correct')
                break

        except ValueError:
            print('please give a number')

asked May 28 '18 at 15:37

Ahmet

2

`aw not in [1,2,3]`... Never use `== False` when there are other ways unless absolutely necessary (which I can't think of a reason to) – OneCricketeer May 28 '18 at 15:39
@cricket_007 - Would the alternative be `if not` instead of `False` ? – May 28 '18 at 15:39
1

@Sveta I think those are equivalent. It's easier to read as `not in` – OneCricketeer May 28 '18 at 15:41
ok thanks for the answer – Ahmet May 28 '18 at 15:42

Error with if statment

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