can someone explain this, I understand that some sort of lazy initialization is taking place, but unable to find any documentation/support for the same.
a = [[0]*3]*3
a[0][0] = 1
print(a)
output:
[[1, 0, 0], [1, 0, 0], [1, 0, 0]]
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Rohith Yeravothula
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It's only one google search away :) – cs95 May 29 '18 at 04:47
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aah I knew it, but I am not able to get the right word to google it. – Rohith Yeravothula May 29 '18 at 04:47
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This isn't related to lazy initialization at all, as far as I can tell – juanpa.arrivillaga May 29 '18 at 05:10