get javascript object out of array based on a field

Question

In an array of objects, I'd like to select the one that has the largest value in one of it's fields.

I get how to select the value itself:

Math.max.apply(Math, list.map(function (o) { return o.DisplayAQI; }))

... but I am not sure how to do the above but return the object itself.

Possible duplicate of [Finding the max value of an attribute in an array of objects](https://stackoverflow.com/questions/4020796/finding-the-max-value-of-an-attribute-in-an-array-of-objects) — Kevin Boucher, May 29 '18 at 15:32

score 6 · Accepted Answer · answered May 29 '18 at 15:33

6

You can use reduce to get the object with the highest DisplayAQI

let list = [ {DisplayAQI : 20}, {DisplayAQI : 100}, {DisplayAQI : 200}, {DisplayAQI : 10} ];

let result = list.reduce((c, v) => c.DisplayAQI > v.DisplayAQI ? c : v);

console.log(result);

Doc: reduce()

answered May 29 '18 at 15:33

Eddie

26,593
6
36
58

1

good solution, as the first thing that hit my mind after listening the question was sorting. But, we can exploit reduce in this case to achieve the result. – Abhishek Kumar May 29 '18 at 15:42
1

Sorting is very slow compared to reduce @AbhishekKumar – baao May 29 '18 at 15:43

score 0 · Answer 2 · answered May 29 '18 at 15:39

0

myObjectArray.sort ( (myObject1, myObject2) => {
return myObject1.field - myObject2.field
})[0]
Simply sort the array according to your field, and get the zero index element.

answered May 29 '18 at 15:39

Abhishek Kumar

2,501
10
25

score 0 · Answer 3 · answered May 29 '18 at 15:52

Alternatively you can sort the array of object in descending order and the get the element from the 0th index

let list = [{
  DisplayAQI: 20
}, {
  DisplayAQI: 100
}, {
  DisplayAQI: 200
}, {
  DisplayAQI: 10
}];

let result = list.sort(function(a, b) {
  return b.DisplayAQI - a.DisplayAQI

})[0];
console.log(result)

get javascript object out of array based on a field

3 Answers3