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i have a list a=[[1,2],[3,4],[5,6]] and i need to check if all elements in sublist are in ascending order (e.g [1,2] is less than [3,4] and [5,6], and [3,4] is less than [5,6] and so on). i use the following function:

def FirstRuleLink (L):
    for i in range(0,len(L)):
        for j in range(0,len(L[i])):
            if L[i][0]<L[i+1][0] and L[i][1]<L[i+1][1]:
                return True
            else:
                return False

but the python gives me error message that index is out of range. so how could i change this code to get the correct output.

Ahmad Aziz
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1 Answers1

0

Here a try :

a = [[1,2],[3,4],[5,6]]

def FirstRuleLink (a):
    for i,nxt_elmnt in zip(a, a[1:]):
        if i[0] <= nxt_elmnt[0] and i[1] <= nxt_elmnt[1]:
            pass
        else:
            return False
Vikas Periyadath
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    @YakymPirozhenko thanks for finding mistakes, please take a look and let me know how I can improve it. – Vikas Periyadath May 30 '18 at 11:36
  • I would go with `all(list(t) == sorted(t) for t in zip(*a))`. Both this and your solution differs from OPs intention of using strict inequalities. Also, you probably mean to `return True` after the for loop. – hilberts_drinking_problem May 30 '18 at 12:18