What is the behavior of a scoped function that contains (xxx::*)

Asked Jun 01 '18 at 14:02

Active Jun 01 '18 at 14:06

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I've been trying to understand the purpose of some code I have been working with. An argument of this form is being passed to a class constructor as a parameter.

(void (Callable::*)(IFN123Struct *, int))

It appears to be a function pointer but I am confused about the scope operators followed by the dereference operator with nothing following it. What is happening here? Does the function itself have a name? What would be the purpose of doing this?

For the record, Callable appears to be an empty class.

edited Jun 01 '18 at 14:06

chux - Reinstate Monica

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asked Jun 01 '18 at 14:02

mreff555

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That would be C++, not C. – Lundin Jun 01 '18 at 14:03
Look up member function pointer. – DeiDei Jun 01 '18 at 14:04
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Very similar question: [SO: What is the meaning of this star (*) symbol in C++? — Pointer to member](https://stackoverflow.com/a/50384782/7478597) (not literally but semantically). – Scheff's Cat Jun 01 '18 at 14:07

What is the behavior of a scoped function that contains (xxx::*)

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