Write the required code to create a dynamic one dimensional integer array

Question

I'm not sure how to answer this question or what it ask exactly for.

Q:Write the required code to create a dynamic one dimensional integer array.

So does it ask just to make dynamic 1D array like this:

new int [5] 
or 
new int [size]

or it ask for another answer like this one:

int size = 5;

int *ptr;

ptr = new int[size];

Thank you.

From where did you get the question? A person? Then ask that person instead. If it's a book, then perhaps you need to check the context. — Some programmer dude, Jun 03 '18 at 04:10
Also, for future reference, unless this question is about pointers, whenever you think "dynamic array" your next thought should *always* be `std::vector`. — Some programmer dude, Jun 03 '18 at 04:14
I think it all depends on whether dynamic refers to the array itself, or the allocation of the array. — samuelnj, Jun 03 '18 at 04:17
Your first answer doesn't assign the array to any integer, so it's a bit less than optimal. https://stackoverflow.com/questions/4029870/how-to-create-a-dynamic-array-of-integers Mayhap this is the answer you're looking for? It details how to properly create a dynamically-allocated array of integers. — Jonathan, Jun 03 '18 at 04:30
IMO the only one that is wrong is `new int [size];` because it doesn't declare `size` and so the code is incomplete. Otherwise they all answer the question. — Galik, Jun 03 '18 at 04:41

score 1 · Answer 1 · answered Jun 04 '18 at 09:13

1

A vector is what you want.

#include <vector>
// some stuff
std::vector<int> A(size);

answered Jun 04 '18 at 09:13

Kurumi Gaming

1 Answers1