Create numpy array with loop

Question

I have some constant , for example, 0.5. So i need to create a numpy array where first element will be equal constant (array[0]=0.5) and next one will be 1, 1.5, 2, 2.5... (previous element plus constant). Lenght of this sequence must be 795. Array what i need looks like:

array = ([0.5,1,1.5,2,2.5.....])

thank you in advance

Try `arange` or `linspace` for a start. – Mad Physicist Jun 04 '18 at 12:35 — Mad Physicist, Jun 04 '18 at 12:35

score 2 · Answer 1 · answered Jun 04 '18 at 12:40

2

Check out this answer - basically what you want is

import numpy
numpy.arange(0.5, 0.5 + 795 * 0.5, 0.5)

answered Jun 04 '18 at 12:40

Alex

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score 0 · Answer 2 · answered Jun 04 '18 at 12:48

0

Using numpy.linspace:

import numpy as np

res = np.linspace(0.5, 795*0.5, num=795)

array([   0.5,    1. ,    1.5,    2. ,    2.5,    3. ,    3.5,    4. ,
      ...
        396.5,  397. ,  397.5])

answered Jun 04 '18 at 12:48

jpp

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Create numpy array with loop

2 Answers2