Working on a regex expression

Question

I want to match ip address which comes in below format, Example : .1.9.2...1.6.8...2.3.4...1.3.4. Not sure how to match the dots between the digits.

Answer 1

Figured out the solution.. So the basic issue was how the base64decoding is done. It varies depending on the OS. So on some machines it was decoding and showing the ip in form [1.9.2...1.6.8...2.5.4...1.2.2.] for such input the above code works perfectly. But i observed in some machine with same code n python version the output came in different format, so on such cases the above code would fail. The best possible solution was to decode the base64 string to consistent format. After alot of hit n try, observed that converting the encoding ndecoding to 'utf-16' resulted in providing a better readable string with now the ip showing up as normal:192.168.254.122 so on this you may use a basic ip match regex and move forward.

Answer 2

This should be what you're looking for:

/([0-9]\.[0-9]\.[0-9])|([0-9]\.[0-9])|([0-9])/g

https://regexr.com/3qihj


Explanation:

There are three capture groups (denoted by parentheses): One for three digits, one for two digits and one for one digit. These are then OR'd using a pipe | character.

Matching the dots between the digits is done using a backslash escape, as a dot character in regex is a meta-character to match any character except a newline.

The regex engine should output an array with a length of 4, corresponding to all four parts of the IP address. The single dots in the middle will be included in each result, the triple dot separators however, will not.

Update with Python Script

I've changed the regex slightly to work with Python.
Works in https://www.tutorialspoint.com/execute_python_online.php

import re
ip = 'W.i.n.3.2._.O.p.e.r.a.t.i.n.g.)h.t.t.p.:././.1.2...1.6.8...4...1.3.5./'

ip = ip.split("h.t.t.p.:././.")[1]
result = re.findall('([0-9]\.[0-9]\.[0-9])|([0-9]\.[0-9])|([0-9])', ip)
ipaddress = ""
for x in range(0, len(result)):
    if len(result[x][0]) > 0:
        ipaddress += result[x][0].replace('.','')
    if len(result[x][1]) > 0:
        ipaddress += result[x][1].replace('.','')
    if len(result[x][2]) > 0:
        ipaddress += result[x][2].replace('.','')
    if(x < len(result) -1):
        ipaddress+= '.'
print (ipaddress)