multidimensional array filtering javascript

Question

I have a multidimensional array

[
  ["apple" , 50],
  ["pie", 45]
  ["steak", 78]
]

I have one another array

["apple","pie"]

How can I filter first array into this result:

[
    ["apple" , 50],
    ["pie", 45]
]

function sorting(value){ 
  var sorted = new Array(); 
  for(var i =0; i <Object.keys(inputArray); i++)
  { 
    if (inputArray[i].keys === value)
    { 
      sorted.push(inputArray[i]); 
    } 
  } 
  return sorted; 
}

this may be your solutionhttps://stackoverflow.com/questions/9206914/how-to-filter-multidimensional-javascript-array — byeke, Jun 05 '18 at 22:14
Please note that Stackoverflow is not a free code writing service. The objective is for you to show what you have attemted to solve your issue and people help you with **your code** when it doesn't work as expected — charlietfl, Jun 05 '18 at 22:14
`function sorting(value){ var sorted = new Array(); for(var i =0; i — Rauf, Jun 05 '18 at 22:15

score 1 · Accepted Answer · edited Jun 07 '18 at 01:38

1

Try this:

var firstArray = [
  ["apple" , 50],
  ["pie", 45],
  ["steak", 78]
];
var secondArray = ["apple","pie"];

var thirdArray = [];

for (var i = 0; i < firstArray.length; i++) {
  if (secondArray.includes(firstArray[i][0])) {
    thirdArray.push(firstArray[i]);
  }
}
console.log(thirdArray);

This is of course used if you don't want to use the .filter method.

edited Jun 07 '18 at 01:38

Pang

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answered Jun 05 '18 at 22:18

Sheshank S.

3,053
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score 0 · Answer 2 · answered Jun 05 '18 at 22:45

0

you can use Array.filter() and Array.includes()

const arr1 = [
  ["apple", 50],
  ["pie", 45],
  ["steak", 78]
]

const arr2 = ["apple", "pie"]

const result = arr1.filter(e => arr2.includes(e[0]))

console.log(JSON.stringify(result))

answered Jun 05 '18 at 22:45

Taki

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why you stringify the end result? – Rauf Jun 05 '18 at 22:46
Just for display purposes , not necessary – Taki Jun 05 '18 at 22:47

multidimensional array filtering javascript

2 Answers2