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Example:

t1=(1,2,3,4)

t2=(5,6,7,8)

print(len(t1)) #Prints: 4

concatenating two tuples

t1=t1+t2

print(t1) #Prints:(1,2,3,4,5,6,7,8)

print(len(t1)) #Prints: 8

repeatation of tuple

t1=t1*3

print(t1) #Prints: (1,2,3,4,1,2,3,4,1,2,3,4)

len(t1) #Prints: 12

Here, in the below code snippet we can see the length of the tuple been changed. Hence, the memory declared for the tuple initially is changed. Please explain this behavior of tuples.

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Puneet Jain
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    The tuple was not changed. The name `t1` was pointed at a new tuple. – Stephen Rauch Jun 06 '18 at 04:38
  • The tuple object is not changed. You've created *new tuple objects* and re-assigned them to the same variable. Use a different variable and you'll see this is so. Note, this is *also the case with list objects* when using concatenation and repetition. And of course, this is the case when you use the `+` and `*` operators with all the numeric types in Python, which are immutable as well. – juanpa.arrivillaga Jun 06 '18 at 04:46

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