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I have two times like t1= "2018-04-28 10:32:32+00:00" and t2= "2018-04-29 20:32:32+00:00" Need to find the number of days between these two days. Actually in the above two days there is 36(means 1 and half day) hours difference is there so I need output as 1.5(which mean 1day and half day). How this is possible with python

U13-Forward
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user3202086
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  • Please show us your attempt on the problem. – Fourier Jun 08 '18 at 12:49
  • refer this link https://stackoverflow.com/questions/1345827/how-do-i-find-the-time-difference-between-two-datetime-objects-in-python – Surya Tej Jun 08 '18 at 12:50
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    This is two separate questions: [Converting a string time to a python datetime object](https://stackoverflow.com/questions/466345/converting-string-into-datetime) and [Finding the difference between two datetime objects](https://stackoverflow.com/questions/1345827/how-do-i-find-the-time-difference-between-two-datetime-objects-in-python). – glibdud Jun 08 '18 at 12:53

1 Answers1

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You can use the timedelta in datetime module. I used parse for more date parsing.

In [2]: from dateutil.parser import parse

In [3]: d1 = parse("2018-04-28 10:32:32+00:00")

In [4]: d2 = parse("2018-04-29 20:32:32+00:00")

In [5]: de = d2 - d1

In [6]: de.total_seconds()/ (60 * 60 * 24)
Out[6]: 1.4166666666666667
iDrwish
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