Convert implode string to interger variable PHP

Question

Suppose after applying implode to an array , I got a String for example :-

$var = 1631075,1631076;

On applying var_dump to $var , I received the output as string(15) "1631075,1631076"

how will I convert entire $var into Integer variable . Such that the var_dump display int(15)1631075,1631076

That doesn't look like a valid integer. Do you want to get the integer `16310751631076`? — Mureinik, Jun 08 '18 at 17:17
I dont understand your question, do you want to create an array of integer? — Azhy, Jun 08 '18 at 17:18
A valid integer will not include and commas only numbers. You format the integer->string to show commas for easy readability later. Strip out any non-numbers and do $var = intval($string_with_only_numbers); — Danny, Jun 08 '18 at 17:21
Plus, that comma is not in the correct place as a thousands separator. — AbraCadaver, Jun 08 '18 at 17:24
I tired applying intval(1631075,1631076) but it only worked on 1st argument i.e int(10)1631075 ; and the 2nd agrument along with comma was left unchanged — Ajanta, Jun 08 '18 at 17:24

score 1 · Answer 1 · answered Jun 08 '18 at 17:30

1

$var = '1631075,1631076';
foreach(explode(',',$var) as $val){
 echo intval($val);
}

or something like

$var = '1631075,1631076';
$integers = explode(',',$var);
$converted = array_map('intval', $integers);

answered Jun 08 '18 at 17:30

Danny

But Sir ,it is giving the output as 16310751631076; how can I get 1631075,1631076 as integer – Ajanta Jun 08 '18 at 17:37
"1631075,1631076" is not an integer and can't be. That can only be a string if you want that inside one variable. – Danny Jun 08 '18 at 17:39
Sir actually I want the final output as [1631075,1631076] (integer format) the required array is Array ( [0] => 1631075 [1] => 1631076 ) – Ajanta Jun 08 '18 at 17:45
Use "intval()" on the array values before handling mathematical functions. Also look at https://stackoverflow.com/questions/8963910/string-to-array-of-integers-php – Danny Jun 08 '18 at 17:51

1 Answers1