I'm trying to write a program that asks the user for a string and tests whether it is a keyword.

Question

import keyword
keywords = (keyword.kwlist)

user_String = input("enter a string: ")

answer = (user_String == keywords)

print ("it is " + str(answer) + " that the string '" + user_String + "' is a 
keyword.")

I'm trying to write a program that asks the user for a string and tests whether it is a keyword. But the trouble I'm having is even if I enter a valid keyword it still prints False

@AngelValenzuela `keywords` is a list, `user_String` is just one element of the list, so `==` always evaluates to `False`. `in` checks instead the membership of the list. — Mr. T, Jun 10 '18 at 08:23
There is a handy method to check the same: `keyword.iskeyword(your_word)`. — Austin, Jun 10 '18 at 08:26

Ryan_DS · Answer 1 · 2018-06-10T08:29:00.180

1

The problem is that you are comparing a string with a collection (keywords).

Instead, try using something like this:

if user_String in keywords:
    print("That is a keyword")
else: 
    print("That is not a keyword")

edited Jun 10 '18 at 08:29

answered Jun 10 '18 at 08:21

Ryan_DS

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Python needs proper indentation for blocks, and semicolons are not necessary (they are *allowed*, but you should not ever need to use them unless your doing code golf and squeezing everything into one line). – Blckknght Jun 10 '18 at 08:26
@Blckknght thanks for that. I'll stick to languages I fully understand to prevent misleading beginners. – Ryan_DS Jun 10 '18 at 08:30

score 0 · Answer 2 · answered Jun 10 '18 at 08:20

0

You should use "contains" function instead of checking equality. Moreover, you have a function called isKeyWord(string) that checks this exact thing.

answered Jun 10 '18 at 08:20

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I'm trying to write a program that asks the user for a string and tests whether it is a keyword.

2 Answers2