Sort list of tuples by element two of all tuples

Question

I want to show the list from the large age to the small age. Here is my list:

player = [("Dmitry", 15), ("Dima", 11), ("Sergey", 14), ("Andrey", 12), ("Nikita", 13)]

I can sort list using name element by player.sort and get this list:

[('Andrey',12),('Dima',11),('Dmitry',15),('Nikita',13),('Sergey',14)]

But I want this list, where ages are large age to small age:

[('Dmitry',15),('Sergey',14),('Nikita',13),('Andrey',12),('Dima',11)]

How I can do this?

score 1 · Answer 1 · answered Jun 11 '18 at 10:08

1

Use sorted with key and reverse

Ex:

player = [("Dmitry", 15), ("Dima", 11), ("Sergey", 14), ("Andrey", 12), ("Nikita", 13)]
print( sorted(player, key=lambda x: x[1], reverse=True) )

Output:

[('Dmitry', 15), ('Sergey', 14), ('Nikita', 13), ('Andrey', 12), ('Dima', 11)]

answered Jun 11 '18 at 10:08

Rakesh

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I want to use sort not sorted since I want to modify original list. – Ramzes666 Jun 11 '18 at 10:25

score 1 · Accepted Answer · answered Jun 11 '18 at 10:08

1

You can achieve your desired sort by using the itemgetter() function as the key parameter and also setting reversed to true so the list is in decending order:

>>> from operator import itemgetter
>>> players = [("Dmitry", 15), ("Dima", 11), ("Sergey", 14), ("Andrey", 12), ("Nikita", 13)]
>>> players.sort(key=itemgetter(1), reverse=True)
>>> print(players)
[('Dmitry', 15), ('Sergey', 14), ('Nikita', 13), ('Andrey', 12), ('Dima', 11)]

answered Jun 11 '18 at 10:08

Sash Sinha

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Thank you for giving links. I think I understand this more than other lambda answers – Ramzes666 Jun 11 '18 at 10:17

score 1 · Answer 3 · answered Jun 11 '18 at 10:09

1

You need to pass a lambda expression as argument for sorted method.

sorted_list = sorted(player, key=lambda tup: tup[1], reverse=True)

Output

[('Dmitry', 15), ('Sergey', 14), ('Nikita', 13), ('Andrey', 12), ('Dima', 11)]

answered Jun 11 '18 at 10:09

Mihai Alexandru-Ionut

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I want to use sort not sorted since I want to modify original list. – Ramzes666 Jun 11 '18 at 10:25

Austin · Answer 4 · 2018-06-11T10:27:42.343

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Another way using lambda but without reverse=True:

player = [("Dmitry", 15), ("Dima", 11), ("Sergey", 14), ("Andrey", 12), ("Nikita", 13)]
player.sort(key=lambda x: -x[1])

# [('Dmitry', 15), ('Sergey', 14), ('Nikita', 13), ('Andrey', 12), ('Dima', 11)]

edited Jun 11 '18 at 10:27

answered Jun 11 '18 at 10:11

Austin

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I want to use sort not sorted since I want to modify original list. – Ramzes666 Jun 11 '18 at 10:25
@Ramzes666 use `.sort()` then. I will update my answer. – Austin Jun 11 '18 at 10:26

Sort list of tuples by element two of all tuples

4 Answers4