16

I have a problem I put my iPhone 6 on iOS 12 beta 1 and that's so a method in my application to close when press on a popup button doesn't works on iOS 12 but works on iOS 11.4.1

That's the method that I used:

UIControl().sendAction(#selector(URLSessionTask.suspend), to: UIApplication.shared, for: nil)

In iOS 11 the app exit properly, in iOS 12 the app doesn't exit just do nothing when press on the popup button.

I know that this is Swift 4.2 and when I rode the news and modifications I haven't seen something like a link with a new method to close app properly.

I need that because I use that to close the app if the person doesn't accept Terms and conditions.

Ashley Mills
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Louis Legout
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    You can call `exit` if I recall correctly – Paulw11 Jun 11 '18 at 13:44
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    `exit()` should work but it's not recommended at all. Just leave the person at the welcome/login screen if they doesn't accept the terms. – diegotrevisan Jun 11 '18 at 13:52
  • exit is depreacted because exit appears to be a crash – Louis Legout Jun 11 '18 at 14:03
  • Technically, an app terminating itself is a crash no matter how you accomplish it and it will likely result in your app being rejected by Apple. – vacawama Jun 11 '18 at 14:04
  • evene exit() is use in Obj-C not in Swift... I'm lost I need because if the app doesn't quit when somebody tries to bypass the terms and conditions... It's complicate, I get the datas of the persons who's accepts and disagrees terms and conditions if somebody works to bypass I will not be able to check that out of that quit. – Louis Legout Jun 11 '18 at 14:11
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    @LouisLegout Well you'll have to clean that data if the user declines the terms. – diegotrevisan Jun 11 '18 at 19:15
  • You are not allowed to call exit(). Its forbidden in the Apple HIG document. As to what to do if your user doesnt accept the option? Don't worry, your not allowed to present a license screen on start up either. That situation will never occur in an accepted app. – Shayne Jun 06 '19 at 06:02

3 Answers3

22

You can call exit method

exit(-1)

or you can use NSXPCConnection.suspend

UIControl().sendAction(#selector(NSXPCConnection.suspend),
                       to: UIApplication.shared, for: nil)

Besides Apple isn't recommending to force terminate your app. It doesn't matter how you do that.

Check this post.

Dávid Pásztor
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U. Benlice
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20

Try this code : 

DispatchQueue.main.asyncAfter(deadline: .now() + 1.0) {
    UIApplication.shared.perform(#selector(NSXPCConnection.suspend))
     DispatchQueue.main.asyncAfter(deadline: .now() + 0.5) {
      exit(0)
     }
}

This will wait 1 sec and app will take 0.5 second to close. You can dim display before this code snippet.

ishwardgret
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5

This would be the easiest way to terminate your App if you don‘t mind triggering a crash error.

// Create an array and "index out of range"
[0][1]
JsW
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