I have the following list of multiple tuples:
[('1', 'Mak'), ('2', 'Sam'), ('3', 'John')]
Type: <type 'list'>
Convert to:
['1,Mak\n', '2,Sam\n', '3,John\n']
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MAK
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1Does something like `[",".join(t) + "\n" for t in lst]` not work? – jedwards Jun 12 '18 at 06:52
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https://stackoverflow.com/questions/15269161/in-python-how-to-join-a-list-of-tuples-into-one-list – The-IT Jun 12 '18 at 06:52
5 Answers
3
string.format with a list comprehension for Python 2.6+
['{}\n'.format(','.join(i)) for i in arr]
# ['1,Mak\n', '2,Sam\n', '3,John\n']
Or with Python 3.6+ using formatted string literals
[f"{','.join(i)}\n" for i in arr]
user3483203
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3
You can use list comprehensions:
l = [('1', 'Mak'), ('2', 'Sam'), ('3', 'John')]
l = [x + ',' + y + '\n' for x, y in l]
so, now l becomes:
['1,Mak\n', '2,Sam\n', '3,John\n']
Rishabh Agrahari
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Using a list comprehension.
l = [('1', 'Mak'), ('2', 'Sam'), ('3', 'John')]
print [",".join(i)+ "\n" for i in l]
or
Using a map with lambda.
Ex:
l = [('1', 'Mak'), ('2', 'Sam'), ('3', 'John')]
print map(lambda x: "{0}\n".format(",".join(x)), l)
Rakesh
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How about this -
>>> l = [('1', 'Mak'), ('2', 'Sam'), ('3', 'John')]
>>> new_list = []
>>>
>>> for x in l:
... new_list.append('%s%s' % (','.join(x), '\n'))
...
>>> new_list
['1,Mak\n', '2,Sam\n', '3,John\n']
>>>
Ejaz
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you can use map and lambda to solve this problem .
#input
your_list = [('1', 'Mak'), ('2', 'Sam'), ('3', 'John')]
#result
result_list = list(map(lambda x:x[0]+x[1]+"\n",your_list))
Pawanvir singh
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