Sorting an array by its keys by another array

Question

I need to sort an array by its keys based on the order of the values in another array. Simple example:

$sort_array = array( 'key1', 'key2' );

$array_that_needs_sorting = array( 'key2' => 'value2', 'key1' => 'value1' );

After sorting, the array should be:

array( 'key1' => 'value1', 'key2' => 'value2' );

score 3 · Answer 1 · answered Feb 22 '11 at 20:24

3

If you know the $sort_array keys are all present in the array that needs to be sorted, you can do this:

$sorted = array_merge(array_flip($keys), $unsorted);

where $keys is $sort_array and $unsorted is $array_that_needs_sorting.

answered Feb 22 '11 at 20:24

Matthew

score 0 · Accepted Answer · edited May 23 '17 at 12:20

0

You might take a look at Sort an Array by keys based on another Array?. It should give you an idea on how to accomplish that.

edited May 23 '17 at 12:20

Community

answered Feb 22 '11 at 19:33

Austin M

Thanks, I've tried all functions in that topic before but it didn't work because my arrays weren't the same size – Jesse Feb 22 '11 at 20:40

score 0 · Answer 3 · answered Feb 22 '11 at 20:12

0

array_merge(array_combine($sort_array, array_fill(0, count($sort_array), null))
   , $array_that_needs_sorting);

answered Feb 22 '11 at 20:12

Explosion Pills

3 Answers3