Converting string to list Python

Question

I currently have a string x = ([15, 16, 17, 18, 19, 20, 21, 22, 23], [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10]). My goal is to convert this entire string into two lists, capturing each numerical value within the list as its own item. x.split(",") returns ['([15', ' 16', ' 17', ' 18', ' 19', ' 20', ' 21', ' 22', ' 23'] and "".join(x) returns '([15 16 17 18 19 20 21 22 23' - neither of which are the result I am looking for. The end result should be two lists, with each number in the list an individual item in numerical format. Does anyone know the best way to accomplish this in python?

`import ast` and then `ast.literal_eval(x)` will give you a tuple of two lists. — ayhan, Jun 13 '18 at 15:42

score 0 · Answer 1 · answered Jun 13 '18 at 15:42

0

Using json:

import json

x = '([15, 16, 17, 18, 19, 20, 21, 22, 23], [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10])'

json.loads(x.replace('(','[').replace(')',']'))

answered Jun 13 '18 at 15:42

Anton vBR

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score 0 · Answer 2 · answered Jun 13 '18 at 15:42

0

>>> first, second = ast.literal_eval('''x = ([15, 16, 17, 18, 19, 20, 21, 22, 23], \
... [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10])'''[4:])
>>> first
[15, 16, 17, 18, 19, 20, 21, 22, 23]
>>> second
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10]

answered Jun 13 '18 at 15:42

Ignacio Vazquez-Abrams

776,304
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score 0 · Answer 3 · answered Jun 13 '18 at 15:45

Use ast.literal_eval:

import ast

x = '([15, 16, 17, 18, 19, 20, 21, 22, 23], [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10])'

x = ast.literal_eval(x)
lst1, lst2 = x[0], x[1]

print(lst1)  # [15, 16, 17, 18, 19, 20, 21, 22, 23]
print(lst2)  # [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10]

Converting string to list Python

3 Answers3