URL regex that will match /x/y but also just /x

Question

I'm following a tutorial, and am getting an 404 error that http://127.0.0.1:8000/restaurants/ is not being matched by

url(r'^restaurants/(?P<slug>\w+)/$', RestaurantListView.as_view())

while http://127.0.0.1:8000/restaurants/x with any x is. How should I rewrite the path to match the url without any additional /x?

... Error message:

Using the URLconf defined in projekt.urls, Django tried these URL patterns, in this order:
admin/
^contact/$
^$
^about/$
^restaurants/(?P<slug>\w+)/$
The current path, restaurants/, didn't match any of these.

You probably need an optional match `^restaurants/(?P\w+/?)?$` — revo, Jun 14 '18 at 00:15
Yes, use an optional group, but you most probably want `r'^restaurants/(?:(?P\w+)/)?$` — Wiktor Stribiżew, Jun 14 '18 at 06:07

score 1 · Answer 1 · answered Jun 14 '18 at 00:43

1

In django 2

path('restuarants/',RestaurantListView.as_view())

In django 1

url(r'^restaurants/$', RestaurantListView.as_view())

answered Jun 14 '18 at 00:43

Ali

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score 1 · Accepted Answer · answered Jun 14 '18 at 08:07

Your regex is matches restaurants/ at the start of input, then captured any 1+ word chars into a group "slug" and then requires and matches / at the end of the string ($ is the end of string anchor.)

You need to wrap the optional part with an optional non-capturing group:

r'^restaurants/(?:(?P<slug>\w+)/)?$'
               ^^^              ^^

The regex matches:

^ - start of input
restaurants/ - a literal restaurants/ substring
(?: - start of a non-capturing group matching...
- (?P<slug>\w+) - 1+ word chars captured into a slug group
- / - a / char
)? - ... end of the non-capturing group matches 1 or 0 times
$ - end of input.

URL regex that will match /x/y but also just /x

2 Answers2