Grab everything after value in variable

Question

In $contents, I'd like to grab everything after the pipe e.g. boss.

$search_for = "micky.mcgurk";
$contents = "micky.mcgurk@somewebsite.com|boss";
$pattern = sprintf('/\b%s@([^|\s]+)\|/m', preg_quote($search_for));

if (preg_match_all($pattern, $contents, $matches)) {
    $submitted_by = implode("\n", $matches[1]);
} else {
   echo "No user found";
}

I think I just need a Regex pattern to grab anything **after** the pipe. — michaelmcgurk, Jun 14 '18 at 12:54

score 4 · Accepted Answer · answered Jun 14 '18 at 12:54

4

$resultat = substr(strrchr($content, '|'), 1);

answered Jun 14 '18 at 12:54

CyrielleDev

156
6

score 1 · Answer 2 · answered Jun 14 '18 at 12:55

1

Why not just use explode?

$contents = "micky.mcgurk@somewebsite.com|boss";
$result = explode("|", $contents);
echo $result[1];

This requires, that mail address and the content after "|" is not having a "|" also ... ;)

answered Jun 14 '18 at 12:55

SiL3NC3

690
6
29

score 1 · Answer 3 · answered Jun 14 '18 at 12:55

1

RegExp way:

$pipe = preg_quote('|', '/');
$regExp = '/.*' . $pipe . '(.*)$/';

The fastest way:

$name = substr($string, strpos($string, '|') + 1);

answered Jun 14 '18 at 12:55

Sergej

2,030
1
18
28

score 1 · Answer 4 · answered Jun 14 '18 at 13:00

To answer about what's happening with your current regex:

([^|\s]+)

matches every continuous non | and whitespace character. Once it encounters that it stops. Because of the capture groups () that is captured.

https://regex101.com/r/DVY3F0/2/

What you want is directly after that though. If you add:

\|\K.*

and remove that previous capture group you will have you want at the 0 index.

https://regex101.com/r/DVY3F0/3/

In full form:

\bmicky\.mcgurk@[^|\s]+\|\K.*

or you could just have it as a vague check for non | until a |.

[^|]+?\|\K.*

https://regex101.com/r/yvzdDu/1/

Grab everything after value in variable

4 Answers4