How to remove characters from each element in a list

Question

I would like to remove the first two characters from each element (which are currently ints) that i have in a list. This is what i have:

lst = [2011,2012,3013]

I would like to get this

lst= [11,12,13]

I do not want a solution with some sort of replace 20 or 30 with '' however.

Possible duplicate of [Last 2 digits of an integer? Python 3](https://stackoverflow.com/questions/41664806/last-2-digits-of-an-integer-python-3) — user3483203, Jun 15 '18 at 18:17
Is my answer ok or are you trying to remove exactly 2 leading digits from every value? In that case what about numbers with 2 or less digits? — Attersson, Jun 15 '18 at 18:46

Attersson · Answer 1 · 2018-06-15T18:41:43.440

Given source= [2011,-2012,-3013] :

dest = [abs(x)%100 for x in source]

dest = [(abs(x)%100)*(1 if x > 0 else -1) for x in source]

dest = list(map(lambda x : str(x)[-2:],source)

dest = list(map(lambda x : ("-" if str(x)[0]=="-" else "")+str(x)[-2:],source))

Gabriel Ben Compte · Answer 2 · 2018-06-15T18:20:57.727

1

You can use:

list = [abs(number)%100 for number in list]

And it's a bad practice to name lists list. Use another name.

edited Jun 15 '18 at 18:20

answered Jun 15 '18 at 18:20

1

Please do not name lists `list` it overrides a builtin. – user3483203 Jun 15 '18 at 18:20
Best suggestion ever :) – mad_ Jun 15 '18 at 18:42

Taohidul Islam · Answer 3 · 2018-06-15T18:27:19.257

You can use module by 100,like:

my_list= [2011,2012,3013]
expected_list = [i%100 for i in my_list]

If you have negative numbers in my_list:

expected_list=[abs(i)%100 for i in my_list]

Or use string slicing:

expected_list = [int(str(i)[2:]) for i in my_list] #[2:],because you want to remove first two numbers

Please try avoid using reserved keywords as you variable name, as you have used list as your variable name.

score 0 · Answer 4 · answered Jun 15 '18 at 18:16

0

Modulo:

just modulo each element with like 100

list= [2011,2012,3013]
for i in range(len(list)):
    list[i] %= 100

answered Jun 15 '18 at 18:16

Tollpatsch

1

Please do not name lists `list`, it overrides a builtin – user3483203 Jun 15 '18 at 18:18

4 Answers4