How to iterate over a list two at a time in Python 3?

Question

I am trying iterate over a list, two at a time. This is my code:

list_1 = [1,3,2,4,3,1,2,7]

The ouput should be like this(the iteration should start from the first element):

Seven, is not there because the iteration in only 2.

This is my try:

nums = [1,3,2,4,3,1,2,7]
for x, y in zip(*[iter(nums)]*2):
    print(x, y)

But my output is:

How can I achieve the proper iteration using Python 3?

Hmm... Does something like `for e in list_1[::2]` work similar to what you are looking for? — Norrius, Jun 17 '18 at 23:26
I added the last question to the duplicate list because since you're just printing elements here, you might consider using [`itertools.islice`](https://docs.python.org/3/library/itertools.html#itertools.islice) to avoid copying your list if it is large. — miradulo, Jun 17 '18 at 23:37

BPL · Accepted Answer · 2018-06-17T23:32:18.860

2

You can use range like this by using step (indexing):

list_1 = [1,3,2,4,3,1,2,7]

for i in range(0,len(list_1),2):
    print(list_1[i])

list_1 = [1,3,2,4,3,1,2,7]

for v in list_1[::2]:
    print(v)

edited Jun 17 '18 at 23:32

answered Jun 17 '18 at 23:26

BPL

1 Answers1