boost python build statically

Question

I googled around how to build statically but I am still struggling to run this. For example this Static linking with boost python, I am getting errror

/python_boost$ g++ -o hello.o -c hello.cpp -Wall -fPIC -I/usr/include/python2.7 /python_boost$ g++ -shared -o libhello.so hello.o -lpython2.7 /usr/lib/x86_64-linux-gnu/libboost_python.a /usr/bin/ld: /usr/lib/x86_64-linux-gnu/libboost_python.a(from_python.o): relocation R_X86_64_32 against `.rodata.str1.8' can not be used when making a shared object; recompile with -fPIC /usr/lib/x86_64-linux-gnu/libboost_python.a: error adding symbols: Bad value collect2: error: ld returned 1 exit status

What am I doing wrong?

Sorry. My question is what is the way to build statically like so that i can load the libhello.so in my python program. I tried various way to build and linked it but no luck. thanks. — jen1982, Jun 18 '18 at 11:14

Maxim Egorushkin · Accepted Answer · 2018-06-18T11:57:41.390

1

Object files intended to be linked into a shared library must be compiled as position-independent code. With gcc and clang that requires -fPIC compiler command line option. Static .a libraries are normally compiled without that option and that is the reason you observe this linker error. See How to compile static library with -fPIC from boost.python for more details.

edited Jun 18 '18 at 11:57

answered Jun 18 '18 at 11:43

Maxim Egorushkin

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Thanks! it . works perfectly.! – jen1982 Jun 26 '18 at 14:02

boost python build statically

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