beginner in java ((char)num) gives zero why

Question

Why when I run this it gives zero instead of the character a:

public class Main {

  public static void main(String[] args) {
    int num = 79;
    char a = 'a';

    System.out.println((char)num);
  }
}

Possible duplicate of [Convert int to char in java](https://stackoverflow.com/questions/17984975/convert-int-to-char-in-java) — ChristophS, Jun 19 '18 at 15:31

score 8 · Answer 1 · answered Jun 19 '18 at 15:30

8

It isn't a zero, it's an uppercase O, which 79 is the ASCII code for.

answered Jun 19 '18 at 15:30

Mureinik

score -1 · Answer 2 · answered Jun 19 '18 at 15:44

-1

You have an typo:

To get the lowercase letter 'a', use 97 instead of 79.

answered Jun 19 '18 at 15:44

ChristophS

Why the downvote? The question is, why the output is zero and not 'a'. This is exaclty the answer (I have tested it). – ChristophS Jun 20 '18 at 04:46
I didn't downvote, but if the problem is just a typo you should comment and flag to close it as off topic rather than adding an answer. – EJoshuaS - Stand with Ukraine Jun 20 '18 at 04:53
OK, thank you, I will regard next time – ChristophS Jun 20 '18 at 05:02

score -1 · Answer 3 · answered Jun 19 '18 at 16:05

-1

When you cast a number to a character it will look the ASCII value of that particular number which in your case is O (CAPITAL O).

If you want to print a use 97

See the ASCII chart for further reference: https://ascii.cl/

answered Jun 19 '18 at 16:05

Sundeep

3 Answers3