list sort not working on part of a list

Question

I am trying to sort part of a list.

My list is

A=[3,2,8,1,0,5,4,6,7,9]

I am able to sort the entire list by A.sort()

A.sort() -> [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]

When I apply sort() on part of the list, it doesn't work as expected. My list remains the same.

A[0:4].sort()-> [3,2,8,1,0,5,4,6,7,9]

I know sorted() will work as expected when I apply on part of a list but I would like to know why sort() does't work on part of the list.

Slicing creates a new list which is getting sorted; but your original list is untouched. — mshsayem, Jun 20 '18 at 14:57
If slicing a list create a new list which gets sorted out, isn't the same applicable to a numpy array? . https://stackoverflow.com/questions/2272819/sort-a-part-of-a-list-in-place . This question has an answer in which they are sorting part of a numpy array using sort. — Abin John Thomas, Jun 20 '18 at 15:21

score 2 · Answer 1 · answered Jun 20 '18 at 15:02

2

Try:

A=[3,2,8,1,0,5,4,6,7,9]
A[0:4] = sorted(A[0:4])
print(A)

Output:

[1, 2, 3, 8, 0, 5, 4, 6, 7, 9]

answered Jun 20 '18 at 15:02

Taohidul Islam

1 Answers1