Why is the order not sorted properly while printing using the loop?

Question

student_name = {"Karrie", "Freya", "Bruno"}

for name in student_name:
print("The student name is {0}".format(name))

I am trying to run this loop but the order the result is in this form

The student name is Freya
The student name is Karrie
The student name is Bruno

**set** is unordered like **dictionary**. Use **list** / **tuple** based on requirements.. — hygull, Jun 21 '18 at 08:27

score 0 · Answer 1 · answered Jun 21 '18 at 08:26

0

Sets are unordered. If you're looking for an ordered collection, use a list:

student_name = ["Karrie", "Freya", "Bruno"]

for name in student_name:
    print("The student name is {0}".format(name))

answered Jun 21 '18 at 08:26

L3viathan

score 0 · Answer 2 · answered Jun 21 '18 at 08:35

0

Use sorted:

student_name = {"Karrie", "Freya", "Bruno"}
for name in sorted(student_name):
    print("The student name is {0}".format(name))

answered Jun 21 '18 at 08:35

Alexander

2 Answers2