Conversion of Dict object into a list of dict object

Question

I have the following dict structure

d = {'Attributes': {'Fifth': 'blind (19.33%)',
                    'First': 'Art (40.0%)',
                    'Fourth': 'Ser (20.0%)',
                    'Second': 'Nat (21.33%)',
                    'Third': 'per (20.67%)'}}

Need to convert into the following structure list of dictionary items

 [   0: {'First': 'Art (40.0%)'},
     1: {'Second': 'Nat (21.33%)'},
     2: {'Third': 'per (20.67%)'},
     3: {'Fourth': 'Ser (20.0%)'},
     4: {'Fifth': 'blind (19.33%)'}
 ]

I need to convert the dict object into a list of key value items, there are fourth twice it should be fith you are right — vinsent paramanantham, Jun 21 '18 at 14:22
lists don't have key, values. They have elements. Do you mean something like `[{'First': 'Art (40.0%)'}, {'Second': 'Nat (21.33%)'}, ...]` or `[(0, {'First': 'Art (40.0%)'}), (2, {'Second': 'Nat (21.33%)'}), ...]`? — FHTMitchell, Jun 21 '18 at 14:23
please post let me check that, please post both the answers thanks — vinsent paramanantham, Jun 21 '18 at 14:24
@vinsentparamanantham No. You post a valid output first, we're not going to guess what you want. You need to help us to help you. — FHTMitchell, Jun 21 '18 at 14:25
Are you trying to sort these items on the percentage in the value, or the meaning of the key? — Patrick Haugh, Jun 21 '18 at 14:28
Sorting can be secondary first i need the data in the list of key value pairs inside the list — vinsent paramanantham, Jun 21 '18 at 14:32
@vinsentparamanantham, Please [edit your quest](https://stackoverflow.com/posts/50970824/edit) to include **valid Python syntax** as desired output. — jpp, Jun 21 '18 at 14:39
No percentage sorting, I need to put them in the order into the list — vinsent paramanantham, Jun 21 '18 at 14:57
@FHTMitchell, should we use format strings: to form the structure https://stackoverflow.com/questions/3294889/iterating-over-dictionaries-using-for-loops — vinsent paramanantham, Jun 21 '18 at 15:15
Look at `list(d['Attributes'].items())`. How does that compare to your desired output? — Patrick Haugh, Jun 21 '18 at 15:18
In what order? Just saying 'in order' doesn't mean anything. — FHTMitchell, Jun 21 '18 at 15:18

Sudarshan · Answer 1 · 2018-06-24T14:45:01.170

First of all, the structure you want as output is not a python list format. Actually, it is not also a dictionary format either.

From your question, I've learned that you want to make a list of dictionaries.

First, make a dictionary element:

0: {'First': 'Art (40.0%)'}

to

{0: {'First': 'Art (40.0%)'}}

Then, you will be ready to make a list of a dictionary and your data structure will look like:

[   {0: {'First': 'Art (40.0%)'}},
     {1: {'Second': 'Nat (21.33%)'}},
     {2: {'Third': 'per (20.67%)'}},
     {3: {'Fourth': 'Ser (20.0%)'}},
     {4: {'Fifth': 'blind (19.33%)'}}
 ]

you can check the structure:

list =  [   {0: {'First': 'Art (40.0%)'}},
     {1: {'Second': 'Nat (21.33%)'}},
     {2: {'Third': 'per (20.67%)'}},
     {3: {'Fourth': 'Ser (20.0%)'}},
     {4: {'Fifth': 'blind (19.33%)'}}
 ]
print(type(a))
print(type(list[0]))

Output:

<class 'list'>
<class 'dict'>

And the code

dict_value = {'Attributes': {'Fifth': 'blind (19.33%)',
                    'First': 'Art (40.0%)',
                    'Fourth': 'Ser (20.0%)',
                    'Second': 'Nat (21.33%)',
                    'Third': 'per (20.67%)'}}

order = {value: key for key, value in enumerate(('First', 'Second', 'Third', 'Fourth', 'Fifth'))}

sorted_form = sorted(dict_value['Attributes'].items(), key=lambda d: order[d[0]])
final_list = [dict(enumerate({key: value} for key, value in sorted_form))]

print(final_list)

produces

[{0: {'First': 'Art (40.0%)'}, 1: {'Second': 'Nat (21.33%)'}, 2: {'Third': 'per (20.67%)'}, 3: {'Fourth': 'Ser (20.0%)'}, 4: {'Fifth': 'blind (19.33%)'}}]

what if my output just has to be, please let me know [{'First': 'Art (40.0%)'}, {'Second': 'Nat (21.33%)'}, {'Third': 'per (20.67%)'}, {'Fourth': 'Ser (20.0%)'}, {'Fifth': 'blind (19.33%)'}] — vinsent paramanantham, Jun 25 '18 at 11:50
just change the `final_list` as `final_list = {item[0]:item[1] for item in sorted_form}` — Sudarshan, Jun 25 '18 at 15:45

score 1 · Accepted Answer · answered Jun 24 '18 at 12:03

Your question is unclear and your desired output is not valid Python. I assume you want a list of dictionaries as your desired output. There are a few steps.

Define your order. Python doesn't know the string "Fourth" should come after "Third".
Apply ordering to dictionary items. Dictionaries are unordered in Python (unless you are using 3.7+).
Use a comprehension with enumerate to construct your list result.

Here's a complete example.

d = {'Attributes': {'Fifth': 'blind (19.33%)',
                    'First': 'Art (40.0%)',
                    'Fourth': 'Ser (20.0%)',
                    'Second': 'Nat (21.33%)',
                    'Third': 'per (20.67%)'}}

order = {v: k for k, v in enumerate(('First', 'Second', 'Third', 'Fourth', 'Fifth'))}

sorter = sorted(d['Attributes'].items(), key=lambda x: order[x[0]])

L = [dict(enumerate({k: v} for k, v in sorter))]

print(L)

[{0: {'First': 'Art (40.0%)'},
  1: {'Second': 'Nat (21.33%)'},
  2: {'Third': 'per (20.67%)'},
  3: {'Fourth': 'Ser (20.0%)'},
  4: {'Fifth': 'blind (19.33%)'}}]

Conversion of Dict object into a list of dict object

2 Answers2