var a = {
"example" : true
};
var x = [a], y = [a];
delete x[0];
console.log(y);
In the above code, would it be possible to have a deleted, not just the reference in x ?
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Brian Tompsett - 汤莱恩
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glider
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What about "delete a;" ? – Krumelur Feb 23 '11 at 21:35
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You want to de-reference the object `a` – John Giotta Feb 23 '11 at 21:39
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1If you want manual memory management, forget it. The object is deleted when the GC sees it fit and when it can prove there are no more references, not a second earlier. – Feb 23 '11 at 21:43
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What do you mean by "delete the object itself"? What would `y` contain? – Ken Feb 23 '11 at 21:44
2 Answers
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That's up to the garbage collector. As long as there's some reference to the object, it will not be garbage collected.
If you want it to be cleaned up, make sure there are no more references.
So to answer your question, no, there's no way to explicitly destroy an object. If a and y[0] are still referencing it, you can't do it from your x variable.
To be clear, x[0] is not referencing a. It is pointing to the same object in memory that a is referencing.
user113716
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1@glider: Aside from dereferencing all the items in the `y` Array, or iterating over the Array to look for it (or using `.indexOf()` if supported), then not really. – user113716 Feb 23 '11 at 21:45
