How to fetch only the url links from the string in python?

Asked Jun 22 '18 at 07:02

Active Jun 22 '18 at 07:09

Viewed 67 times

How do I fetch only the links from my file shown below:

Jun 15 16:26:21 dnsmasq[1979]: query[A] fd-geoycpi-uno.gycpi.b.yahoodns.net from 192.168.1.33 

Jun 15 16:26:30 dnsmasq[1979]: query[A] armdl.adobe.com from 192.168.1.24

Jun 15 16:26:32 dnsmasq[1979]: query[A] updates.installshield.com from 192.168.1.118

Note: the links may or may not start with "www." or end with ".com" (example: armdl.adobe.com, fd-geoycpi-uno.gycpi.b.yahoodns.net) but the "query[A]" before the link and "from" after the link remains same for every string. Thank you.

asked Jun 22 '18 at 07:02

Manoj Jahgirdar

3

Maybe [`s.split()[5]`](http://rextester.com/DCLK45366)? Well, *the "query[A]" before the link and "from" after the link remains same for every string* means you just want to extract a string between two strings, right? Closing as a dupe. – Wiktor Stribiżew Jun 22 '18 at 07:04
s.split()[5] should work. – Raman Mishra Jun 22 '18 at 07:06
@WiktorStribiżew yes exactly I want to extract the string between the given claws... – Manoj Jahgirdar Jun 22 '18 at 07:07
1

I have found 2 SO threads that answer your question. If you decide to use a regex, do not forget to escape `[` in the pattern to match a literal `[`. – Wiktor Stribiżew Jun 22 '18 at 07:11
1

Thank you @WiktorStribiżew it worked – Manoj Jahgirdar Jun 22 '18 at 08:24

How to fetch only the url links from the string in python?

0 Answers0