How to convert list to dictionary without messing up the sequence

Question

when i used a function it messed up the sequence of my dictionary

arr = ['loyd1', 'loyd2', 'loyd3', 'loyd4']
list =  {k: 0 for k in arr}
{'loyd1': 0, 'loyd3': 0, 'loyd2': 0, 'loyd4': 0}

Possible duplicate of [Dictionaries: How to keep keys/values in same order as declared?](https://stackoverflow.com/questions/1867861/dictionaries-how-to-keep-keys-values-in-same-order-as-declared) — Aran-Fey, Jun 25 '18 at 12:39

score 0 · Accepted Answer · answered Jun 25 '18 at 12:49

0

You can use OrderedDict() to keep the same order in which the dictionary was created.

from collections import OrderedDict


arr = ['loyd1', 'loyd2', 'loyd3', 'loyd4']
dico =  OrderedDict((k, 0) for k in arr)

answered Jun 25 '18 at 12:49

Divadrare

score 0 · Answer 2 · answered Jun 25 '18 at 12:58

0

please use OrderDict!

from collections import OrderDict
arr = ['loyd1', 'loyd2', 'loyd3', 'loyd4']
res = OrderedDict()
res = {i: 0  for i in arr}
print(res)

answered Jun 25 '18 at 12:58

jian0lu

score -1 · Answer 3 · edited Jun 25 '18 at 15:14

-1

If you do not want to import any module, simply do this:

arr = ['loyd1', 'loyd2', 'loyd3', 'loyd4']
dict={}
for k in arr: 
    dict[k]=0

edited Jun 25 '18 at 15:14

Thomas Ayoub

answered Jun 25 '18 at 13:06

MOHIT SHARMA

That is no different from a dict comprehension, except for the fact that it's more verbose. – Aran-Fey Jun 25 '18 at 14:41

3 Answers3