Python - time data does not match format

Question

I have a date format that looks like this Apr 9 2018 and would like to convert it to something like 2018-04-19

My sample code looks like this:

datetime.strptime(unformated_date, '%m %d %y').strftime('%y-%m-%d') where unformated_date="Apr 9 2018"

But I am getting the error time data ' Apr 9 2018' does not match format '%m %d %y'

How could I achieve this in python? Thanks in advance

You can use datetime or dateutils library. Check this answer: https://stackoverflow.com/questions/466345/converting-string-into-datetime — Krishna Wadhwani, Jun 25 '18 at 16:24

Rakesh · Accepted Answer · 2018-06-25T16:29:52.353

3

Your date string is "%b %d %Y"

Ex:

import datetime
unformated_date = "Apr 9 2018"    
print( datetime.datetime.strptime(unformated_date, "%b %d %Y").strftime('%y-%m-%d') )
print( datetime.datetime.strptime(unformated_date, "%b %d %Y").strftime('%Y-%m-%d') )

Output:

18-04-09
2018-04-09

MoreInfo

edited Jun 25 '18 at 16:29

answered Jun 25 '18 at 16:23

Rakesh

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Thanks! what does the 'b' mean? – Timal Peramune Jun 25 '18 at 16:25
1

`%b` == Month as locale’s abbreviated name. – Rakesh Jun 25 '18 at 16:27
Is there a way for the year to show up as '2018' instead of just '18' ? – Timal Peramune Jun 25 '18 at 16:28
Sure use `%Y` capital Y – Rakesh Jun 25 '18 at 16:29

Python - time data does not match format

1 Answers1